2025 AMC 8 Problems/Problem 11: Difference between revisions

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The 2025 AMC 8 is not held yet. Please do not post false problems.

Revision as of 06:06, 23 February 2024 view source Theumbrellaacademy (talk \| contribs) editor 99 edits 2025 AMC 8 Problem 11		Revision as of 12:43, 4 August 2024 view source Sixthgradebookworm927 (talk \| contribs) editor 67 edits No edit summary Newer edit →
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	~~Find the smallest positive integer <math>k</math> such that <math>(2^{91}+k)</math>~~ is ~~divisible by <math>127</math>~~.		The 2025 AMC 8 is not held yet. Please do not post false problems.

	~~<math>\textbf{(A)}\ 122 \qquad \textbf{(B)}\ 123 \qquad \textbf{(C)}\ 124 \qquad \textbf{(D)}\ 125 \qquad \textbf{(E)}\ 126</math>~~