Art of Problem Solving

Octagon: Difference between revisions

m i can't seem to eliminate the double root in the circumradius ..
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Each internal [[angle]] of a [[Regular polygon | regular]] octagon measures 135 [[degree (geometry) | degrees]], so the sum of the angles is <math>1080^{\circ}</math>.
Each internal [[angle]] of a [[Regular polygon | regular]] octagon measures 135 [[degree (geometry) | degrees]], so the sum of the angles is <math>1080^{\circ}</math>.


[[Area]]: <math>2s^2(\sqrt{2} + 1)</math>
[[Area]]: <math>2s^2(1 + \sqrt{2})</math>


[[Apothem]]: <math>\frac{s(\sqrt{2} + 1}{2}</math>
[[Apothem]]: <math>\frac{s(1+ \sqrt2 )}{2}</math>


[[Inradius]]: <math>\frac{s(\sqrt{2} + 1}{2}</math>
[[Inradius]]: <math>\frac{s(1+ \sqrt2 )}{2}</math>


[[Circumradius]]:  <math>s\sqrt{1 + \frac{\sqrt{2}}{2}}</math>
[[Circumradius]]:  <math>\frac{s\sqrt{4+2\sqrt{2}}}{2}</math>




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[[Category:Geometry]]

Latest revision as of 19:40, 14 October 2007

An octagon is an eight-sided polygon.

Regular octagons

Each internal angle of a regular octagon measures 135 degrees, so the sum of the angles is $1080^{\circ}$.

Area: $2s^2(1 + \sqrt{2})$

Apothem: $\frac{s(1+ \sqrt2 )}{2}$

Inradius: $\frac{s(1+ \sqrt2 )}{2}$

Circumradius: $\frac{s\sqrt{4+2\sqrt{2}}}{2}$


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