2021 JMPSC Sprint Problems/Problem 2: Difference between revisions
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==Solution== | ==Solution== | ||
It is generally best to use the smallest number of coins with the most value, specifically the quarters, for taking away a big chunk of the problem. We are able to fit <math>11</math> quarters, or <math>\$2.75</math> into <math>\$2.78</math>. That only leaves <math>3</math> cents. We cannot put any nickels nor dimes, therefore we require three pennies to get a total of <math>\$2.78</math>. | |||
The least number of coins Brady can use to pay off <math>\$2.78</math> will be <math>14</math> coins. | |||
-OofPirate | |||
== Solution 2 == | |||
You want as many quarters in order to cut down on the number of coins. The most amount of quarters you can have is <math>11</math>. Since you can't use three cents on anything other than pennies, the remaining coins are <math>3</math> pennies. Therefore <math>11+3=14</math> | |||
- kante314 - | |||
==See also== | |||
#[[2021 JMPSC Sprint Problems|Other 2021 JMPSC Sprint Problems]] | |||
#[[2021 JMPSC Sprint Answer Key|2021 JMPSC Sprint Answer Key]] | |||
#[[JMPSC Problems and Solutions|All JMPSC Problems and Solutions]] | |||
{{JMPSC Notice}} | |||
Latest revision as of 09:09, 12 July 2021
Problem
Brady has an unlimited supply of quarters (\$0.25), dimes (\$0.10), nickels (\$0.05), and pennies (\$0.01). What is the least number (quantity, not type) of coins Brady can use to pay off \$
?
Solution
It is generally best to use the smallest number of coins with the most value, specifically the quarters, for taking away a big chunk of the problem. We are able to fit 
quarters, or 
into 
. That only leaves 
cents. We cannot put any nickels nor dimes, therefore we require three pennies to get a total of .
The least number of coins Brady can use to pay off will be 
coins.
-OofPirate
Solution 2
You want as many quarters in order to cut down on the number of coins. The most amount of quarters you can have is . Since you can't use three cents on anything other than pennies, the remaining coins are pennies. Therefore 
- kante314 -
See also
The problems on this page are copyrighted by the Junior Mathematicians' Problem Solving Competition. 
