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Revision as of 16:48, 9 February 2019

Problem 38

If $f(a)=a-2$ and $F(a,b)=b^2+a$, then $F(3,f(4))$ is:

$\textbf{(A)}\ a^2-4a+7 \qquad \textbf{(B)}\ 28 \qquad \textbf{(C)}\ 7 \qquad \textbf{(D)}\ 8 \qquad \textbf{(E)}\ 11$

Solution

We find $f(4)=(4)-2=2$, so $F(3,f(4))=F(3,2)=(2)^2+3=\boxed{\textbf{(C) }7}$.

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