2010 UNCO Math Contest II Problems/Problem 3: Difference between revisions
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== Solution == | == Solution == | ||
The solution rst must factor <math>48=2^{4}\cdot{3}</math> and the numbers must be DISTINCT. <math>3+4+4=11</math> fails the distinct test so <math>2+4+6=12</math> is the solution. | |||
== See also == | == See also == | ||
Latest revision as of 01:46, 13 January 2019
Problem
Suppose 
, and 
are three different positive integers and that their product is 
, i.e., 
What is the smallest possible value of the sum 
?
Solution
The solution rst must factor 
and the numbers must be DISTINCT. 
fails the distinct test so 
is the solution.
See also
| 2010 UNCO Math Contest II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
| All UNCO Math Contest Problems and Solutions | ||
