Art of Problem Solving

2010 AMC 10B Problems/Problem 7: Revision history

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  • curprev 14:3014:30, 5 August 2010 Srumix talk contribs 600 bytes +600 Created page with 'The triangle is isosceles. The height of the triangle is therefore given by <math>h = \sqrt{10^2 - ( \dfrac{12}{2})^2} = \sqrt{64} = 8</math> Now, the area of the triangle is <…'