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1991 AJHSME Problems/Problem 2: Revision history

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4 July 2013

7 August 2009

  • curprev 14:5914:59, 7 August 2009 5849206328x talk contribs 386 bytes +386 Created page with '==Problem== <math>\frac{16+8}{4-2}=</math> <math>\text{(A)}\ 4 \qquad \text{(B)}\ 8 \qquad \text{(C)}\ 12 \qquad \text{(D)}\ 16 \qquad \text{(E)}\ 20</math> ==Solution== <cma…'
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