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1965 AHSME Problems/Problem 6: Revision history

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18 July 2024

29 January 2020

  • curprev 14:0914:09, 29 January 2020 Dividend talk contribs 488 bytes +488 Created page with "== Problem 6== If <math>10^{\log_{10}9} = 8x + 5</math> then <math>x</math> equals: <math>\textbf{(A)}\ 0 \qquad \textbf{(B) }\ \frac {1}{2} \qquad \textbf{(C) }\ \frac {..."
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