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1956 AHSME Problems/Problem 15: Revision history

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12 February 2021

  • curprev 19:0719:07, 12 February 2021 Coolmath34 talk contribs 645 bytes +645 Created page with "== Problem == The root(s) of <math>\frac {15}{x^2 - 4} - \frac {2}{x - 2} = 1</math> is (are): <math>\textbf{(A)}\ -5\text{ and }3\qquad \textbf{(B)}\ \pm 2\qquad \textbf{..."
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