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1954 AHSME Problems/Problem 25: Revision history

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28 February 2020

6 June 2016

  • curprev 13:4913:49, 6 June 2016 Katzrockso talk contribs 474 bytes +474 Created page with "== Problem 25== The two roots of the equation <math>a(b-c)x^2+b(c-a)x+c(a-b)=0</math> are <math>1</math> and: <math> \textbf{(A)}\ \frac{b(c-a)}{a(b-c)}\qquad\textbf{(B)}\ ..."
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