27 June 2022

• curprev 16:4016:40, 27 June 2022 Doctor seventeen talk contribs 1,072 bytes +1 →Solution
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25 January 2020

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30 April 2018

• curprev 18:1118:11, 30 April 2018 Edonahey5 talk contribs 981 bytes +981 Created page with "==Problem 20== If <math>y=x+\frac{1}{x}</math>, then <math>x^4+x^3-4x^2+x+1=0</math> becomes: <math>\textbf{(A)}\ x^2(y^2+y-2)=0 \qquad \textbf{(B)}\ x^2(y^2+y-3)=0\\ \tex..."