View source for 2005 CEMC Gauss (Grade 7) Problems/Problem 10

== Problem ==

In relation to Smiths Falls, Ontario, the local time in St. John’s, Newfoundland, is <math>90</math> minutes ahead, and the local time in Whitehorse, Yukon, is <math>3</math> hours behind. When the local time in St. John’s is 5:36 p.m., the local time in Whitehorse is

<math>\text{(A)}</math> 1:06 p.m. <math>\text{(B)}</math> 2:36 p.m. <math>\text{(C)}</math> 4:06 p.m. <math>\text{(D)}</math> 12:06 p.m. <math>\text{(E)}</math> 10:06 p.m.

== Solution ==

When it is 5:36 p.m. in St. John’s, it is <math>90</math> minutes or <math>3/2</math> hours earlier in Smiths Falls, so it is 4:06 p.m. in Smiths Falls.  When it is 4:06 p.m. in Smiths Falls, it is 3 hours earlier in Whitehorse, so it is 1:06 p.m. in Whitehorse.  The answer is <math>A</math>.

==See Also==

{{CEMC box|year=2005|competition=Gauss (Grade 7)|num-b=9|num-a=11}}